- #1

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[The given equation is mgh = 1/2*Iw^2 + 1/2*mv^2 + Tf * theta

My attempt was a bit of a stab in the dark as i am useless with rearranging equations.

I = mgh/w^2 + 1/2*mv^2 + Tf * theta

Many thanks

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- Thread starter Hussman
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- #1

- 9

- 0

[The given equation is mgh = 1/2*Iw^2 + 1/2*mv^2 + Tf * theta

My attempt was a bit of a stab in the dark as i am useless with rearranging equations.

I = mgh/w^2 + 1/2*mv^2 + Tf * theta

Many thanks

- #2

- 993

- 13

First step: Transfer those two terms on the RHS not involving I to the LHS.

- #3

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ok so you end up with

mgh - 1/2*mv^2 - Tf*theta = 1/2*Iw^2

Would the lhs be divided by 1/2 w^2?

Thanks

mgh - 1/2*mv^2 - Tf*theta = 1/2*Iw^2

Would the lhs be divided by 1/2 w^2?

Thanks

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- #4

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- #5

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Nice one cheers

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