# Help needed with trigonometric word problem

amd123

## Homework Statement

http://img135.imageshack.us/img135/4150/trighelp.jpg [Broken]

## The Attempt at a Solution

http://img18.imageshack.us/img18/8480/workz.jpg [Broken]

Please help I'm totally confused, if anyone can help I can offer a reward of monetary value :).

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Homework Helper
Gold Member
You are looking for the point along the 40 foot side at which the height from floor to beam is 16 inches. When you find the value, you want to see if it is more than 2 feet away from the righthand side of the wall.

amd123
Oh thank god, if it works I owe you BUT i don't have any idea how to do that :(
Also are my calculations correct? When i subtract 8.6 from 10 i get 1.4 feet but when i take the sin of 6 degrees * h2 i get 4.2 feet for the height of the beam?

Homework Helper
Gold Member
Also, since you have a 10 by 40 right-triangle, you should be able to find the measures of the other two angles, and therefore should be able to find the other angle measures in the diagram. Then, you have that lower right-triangle, on the bottom. The angle on the left is easy: the found angle above, the 12 degree, the desired lower angle - their sum is 90 degrees.

amd123
Also, since you have a 10 by 40 right-triangle, you should be able to find the measures of the other two angles, and therefore should be able to find the other angle measures in the diagram. Then, you have that lower right-triangle, on the bottom. The angle on the left is easy: the found angle above, the 12 degree, the desired lower angle - their sum is 90 degrees.