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Homework Help: Help needed

  1. Jul 19, 2005 #1
    i know this is basic suff, but forget it, can u plz tell me how to do this question

    how much work is done in moving a mole of electrons around a circut using a 6v voltage( 1 mole of electrons is 6.023 x 10 power 23 electrons


    answer is w = qv = 5.78 x 10power5j
  2. jcsd
  3. Jul 19, 2005 #2
    Do you know the charge on an electron? To find the total charge, q, multiply the charge of one electron by the number of electrons...
  4. Jul 19, 2005 #3
    yes the charge of an eleectron is -1.6 x10power-19

    sorry dont understand,

    v =w/q


    v is potential difference in volts
    w is work done by field in joules
    q is charge being ppushed in coulombs

    so w= 6 x q( which i thought was the mole of electrons, which is 6.023 x 10power23 right?)
  5. Jul 19, 2005 #4
    If you know q is charge, as measured in coulombs, why would you think it was 6.022 x 10^23, which is the number of electrons?

    If you had one electron, the work done would be, W = QV = (1.6 x 10^-19)*6..
  6. Jul 19, 2005 #5
    k, got confused there, i hate this topic, i like the space one!

    i see now:) so

    w = 6* ( 1.6 x 10^-19 x number of electrons (6.023 x 10^23)
  7. Jul 19, 2005 #6
    Yes, that's correct :smile:.
  8. Jul 19, 2005 #7
    thanks, i have been lazey thesee holidays:P

    seen these forums once before and when i formated my computer i lost the address, just found it again, i quess this is British forum(the mother land!)
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