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Help on graph

  1. Nov 6, 2007 #1
    ok i was graphing y=-e^x e=2.1783 and i got this up and down line growing from negative to positve, i have no clue what the hell im looking at, ive attached what i got tell if im right or wrong, point in the right direction if you could
     

    Attached Files:

  2. jcsd
  3. Nov 6, 2007 #2

    JasonRox

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    Take the graph of e^x and flip it upside down.
     
  4. Nov 6, 2007 #3
    thank you that was driving me nuts
     
  5. Nov 6, 2007 #4

    Integral

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    The graph you have posted is NOT [itex] - e^x [/itex]
     
  6. Nov 7, 2007 #5

    HallsofIvy

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    Since you don't say HOW you got that graph, there's not much more we can tell you!
    (It looks to me something like y= excos(x).)
     
  7. Nov 7, 2007 #6
    It looks to me like a naive attempt at (-e)^x, judging from the oscillations. Of course, the points between the integers are all wrong. That MAY have been the logic behind it, but I don't know...
     
  8. Nov 7, 2007 #7
    poohbear, there is still some confusion. Are you trying to graph (-e)^x or -(e^x). There is a big difference, and writing -e^x is slightly ambiguous (although it implies the latter of the two I wrote).

    Moo Of Doom, you are right it looks like (-e)^x (with connecting lines drawn in the undefined parts) but when x is 2 f(x) should be around 7.4 and in his document 4 < f(2) < 6 which actually satisfies neither of the two possibilities mentioned.
     
  9. Nov 7, 2007 #8
    I thought it was odd too, but when you look at the original post, he says

    and 2.17822 is about 4.74. I think he mistyped his value for e when he plotted the points as well. Makes everything pretty confusing, doesn't it?
     
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