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Help on homework

  • #1
Q: When a metal pipe is cut into two pieces, the lowest resonance frequency for one piece is 230 Hz and the other is 436 Hz.(a) what resonant frequency would have been produced by the original length of pipe?

From what I have so far:

1) the length of the two original pipes added together would give me the resonant frequency

2) the length of each pipe can be found by dividing the lamda for frequency for each pipe by two

3) Lamda can be found by the formula "v=(lamda)f," unfortunately I do not know the "v." What set of formula's or algebra can I use to find "v" ?

Thx ahead of time.
 

Answers and Replies

  • #2
Tom Mattson
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ayrricjones said:
3) Lamda can be found by the formula "v=(lamda)f," unfortunately I do not know the "v." What set of formula's or algebra can I use to find "v" ?
It's the speed of sound, so you would just look it up.
 

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