- #1
noblerare
- 50
- 0
Homework Statement
[tex]\int[/tex][tex]\frac{cosxdx}{\sqrt{1+cosx}}[/tex]
Homework Equations
n/a
The Attempt at a Solution
Well I tried:
u=cosx
x=arccosx
dx=[tex]\frac{-du}{\sqrt{1-u^2}}[/tex]
Plugging them back into the integral gives me:
-[tex]\int[/tex][tex]\frac{udu}{\sqrt{1-u^2}\sqrt{1+u}}[/tex]
I don't know where to go from there.
I've also tried:
[tex]\int[/tex][tex]\frac{cosx\sqrt{1-cosx}dx}{sin^2x}[/tex]
or:
[tex]\int[/tex][tex]\sqrt{\frac{cos^2x}{1+cosx}}dx[/tex]
But I don't know where to go from any of the above attempts. Any help would be greatly appreciated.