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## Homework Statement

Two particles, separated by an enormous distance, approach each other. Each has an initial speed of 3.0 X 10^6 m/s. Calculate their minimum separation, assuming no deflection from their original path. The mass of a partical is 6.6 X 10^-27 kg.

Particle charge = 3.2 X 10^-19 C

Given:

V = 3.0 X 10^6m/s

mass of particle = 6.6 X 10^-27 kg

r = ?

## Homework Equations

E = Eprime

Fe = kq1q2/r^2

## The Attempt at a Solution

EE + EK = EEprime + EKprime

Kq1q2/r + 1/2 mv^2 = Kq1q2/r + 1/2m(vprime)^2

Dont know where to go from there