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Homework Statement
I need some advice on prooving this formula (f is an arbitrary function):
[itex]\sum^{N}_{t=1}[/itex][itex]\sum^{N}_{s=1}[/itex]f(t-s)=[itex]\sum^{N-1}_{τ=-Ν+1}[/itex](N-|τ|)f(τ)
Thanks in advance
A summation formula is a mathematical expression that allows you to calculate the sum of a series of numbers. It is denoted by a capital Greek letter sigma (Σ) and is followed by the numbers to be summed, along with their corresponding coefficients. For example, the summation formula for the series 1+2+3+4+5 would be written as Σn, where n represents the number being summed.
To prove a summation formula, you will need to use mathematical induction. This method involves showing that the formula holds true for a specific value (usually 1 or 0), and then proving that if the formula holds for a particular value, it also holds for the next value. By repeating this process, you can show that the formula holds true for all values in the series.
The steps to proving a summation formula using mathematical induction are as follows:
Step 1: Show that the formula holds true for the first value in the series (usually 1 or 0).
Step 2: Assume that the formula holds true for a particular value (usually denoted as k).
Step 3: Use this assumption to prove that the formula also holds true for the next value (k+1).
Step 4: Repeat this process for all values in the series, showing that the formula holds true for each value.
Step 5: Conclude that the formula holds true for all values in the series, thereby proving its validity.
Yes, a summation formula can be used for infinite series. However, in order for the formula to be valid, the series must be convergent, meaning that the sum of the series approaches a finite value as the number of terms increases. In these cases, the summation formula is denoted by the infinity symbol (∞), and the series is written as Σn=1 to ∞.
Some common summation formulas include:
- Sum of integers: Σn = n(n+1)/2
- Sum of squares: Σn^2 = n(n+1)(2n+1)/6
- Sum of cubes: Σn^3 = (n(n+1)/2)^2
- Geometric series: Σar^n = a(1-r^n)/(1-r), where a is the first term and r is the common ratio
- Harmonic series: Σ1/n = ln(n+1), where ln is the natural logarithm