Hey - just asking for some help on some electric potential energy questions. First I used the equation 1/2mv^2 = q(Va-Vb) so v = sqrt (((2)(25000)(q)) / m ) and Va-Vb = W / q, so q = W/(Va-Vb) but then i'm stuck and dont know where to go from there since the mass and the charge (q) isnt' given. So I said that mgh(of a) = 1/2mv^2 (of b) so (9.8)h = 1/2(42^2), h = 90. That means that the potential difference between A and B is 90?, and point A is at a higher potential since the charge/mass flows TO B FROM A? This one I'm completely lost. Leme think, so Va-Vb = 320V = W/q (and q = 1300). So 320V = W / 1300, W = 416,000J? and that just needs to be converted into horsepower?