Help please. I dont understand

  • Thread starter name_ask17
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The difference in answer is by a factor of 28.97/44.01 = 0.658. So, either 6.0 or 3.948. Still, you should consider both with ppm.In summary, the conversation discusses the calculation of the number of carbon monoxide molecules in 1.0 L of air in the United States in 1991, given an estimated average concentration of 6.0 ppm. The equation pv=nrt is used, with pressure, volume, and temperature given. The question of whether ppm is weight/weight or volume/volume is raised, as it affects the final answer.
  • #1
name_ask17
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Homework Statement



The estimated average concentration of carbon monoxide in air in the United States in 1991 was 6.0 ppm. Calculate the number of CO molecules in 1.0 L of this air at a pressure of 601 torr and a temperature of 20.°C.



Homework Equations



pv=nrt

The Attempt at a Solution

I tried this and using pv=nrt
pressure was converted to torr
volume was 1
r was taken as 8.31
temp was converted into K
and then...
n was solved for, and muktiplied by avagadro's number
Am i missing something? am i supposed to include the ppm?
i am so confused.
please help.
 
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  • #2
ppm is a concentration, so yes, it should be included in your calculations - otherwise you calculated just the number of molecules of all gases in the given volume.

Unfortunately, question is ambiguous - it doesn't state whether ppm is weight/weight or volume/volume.
 

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