Hello! I have an integral problem here dealing volume. I think I have a good idea on how to get to the answer, but I'm stuck on finding the antiderivative. Here's my work! Thanx in advance to any help! 1. The problem statement, all variables and given/known data There is a solid lying between planes perpendicular to the x axis from x= -[tex]\pi[/tex]/3 to [tex]\pi[/tex]/3. Cross sections on the x axis are perpendicular to the x axis are circular disks where the diameter goes from the curve y=tanx to y=secx. Find the volume (by slicing). 2. Relevant equations All righty. So far I have graphed the two curves from the two x endpoints. since y=secx is above y=tanx L=f(x)=secx-tanx A(x)=([tex]\pi[/tex]D^2)/4 Therefore A(x)=([tex]\pi[/tex](secx-tanx)^2)/4 For volume: I have the integral from [tex]\pi[/tex]/3 to -[tex]\pi[/tex]/3 A(x) 3. The attempt at a solution For the solutionn, I know that I have to find the antiderivative of A(x) and take the difference from the two endpoints. Which the the step that I'm stuck at if I have done everything else correct. Could I have missed a step, or actually am off track with this problem? Thanks!