Help simplifying an equation

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  • Thread starter rede96
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  • #1
659
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Hi, just wondering if anyone could help me simplify (if possible) the following two equations.

x = sin((cos(((1-(cos(θ/2)^2))*360)/2)+1)/2*θ)*(d/2)

x = cos((cos(((1-(cos(θ/2)^2))*360)/2)+1)/2*θ)*d/2)*2

My math is pretty crap, so any help would be appreciated.

Thanks
 

Answers and Replies

  • #3
659
14
Apart from some formatting and ##1-\cos^2(x) = \sin^2(x)## , there is not much to simplify. It has an interesting contour plot, however.

Oh well, will have to use them in the current form. Thanks anyway.

If you don't mind me asking (as I really am crap at math) why is the contour plot interesting?
 
  • #4
14,897
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Oh well, will have to use them in the current form. Thanks anyway.

If you don't mind me asking (as I really am crap at math) why is the contour plot interesting?
It looks like right from a seismograph or a piece of modern art.
 
  • #5
member 587159
It looks like right from a seismograph or a piece of modern art.

Tbh, I didn't see anything special in it either.
 
  • #6
14,897
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For the record (Source: https://www.wolframalpha.com/input/?i=sin((cos(((1-(cos(θ/2)^2))*360)/2)+1)/2*θ)*(d/2))
gif&s=59.gif
 
  • #7
703
13
I typed your equation and "simplify" into wolframalpha, and this is what I got
It has a simpler looking form for x, d and theta real.
 
  • #8
DrClaude
Mentor
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3,999
It has an interesting contour plot, however.
My guess is that this is incorrect, as the 360 smells of degrees, leading to a much too rapid oscillation and a crappy contour plot. Change the 360 to 2*pi and you get something much more banal.

I typed your equation and "simplify" into wolframalpha, and this is what I got
It has a simpler looking form for x, d and theta real.
This is the same result as
##1-\cos^2(x) = \sin^2(x)##
 

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