# Help solve this integral (by parts possibly)

1. Aug 6, 2015

### Engineerbrah

QUESTION:

The question is to find the improper integral of (x^1/2)/lnx dx.

MY ATTEMPT:
1)I tried it byparts, by taking 1/ln x as 'u' or the first function but i got stuck.

2)Alternatively, I tried substituting x=e^2t in hopes to eliminate ln for a simpler byparts integration, but that didn't work
out.

2. Aug 6, 2015

### Devin

You can apply parts directly. Apply parts in the form such that the evaluation of the new integral involves the derivative of (1/lnx).

3. Aug 6, 2015

### Engineerbrah

I tried it this way. The furthest I got was

(2*(x)^(1/2))/lnx - Integral of (2/((x)^(1/2))(lnx)^2 dx

Still not able to attain the answer.

4. Aug 6, 2015

### Devin

I believe this to be the way to approach. Then the evaluation of the new integral is straightforward.

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Last edited by a moderator: Aug 6, 2015