- #1

Yura

- 39

- 0

__+__rule for a solution with complex numbers that there would always be a conjugate solution of it. so i figured that the last solution would be (x=-i) but when i try and solve it i keep getting different answers and they are all non zero.

i think i may be doing something wrong with the powers of the

**(-i)**or it might be that i thought wrong and (x=-i) is not a solution.

could someone please confirm ths for me?

here is the equation:

x^3 - (2-i)*x^2 + (2-2*i)*x - 4 = 0

im trying to solve for:

**(-i)**^3 - (2-i)*

**(-i)**^2 + (2-2*i)*

**(-i)**- 4 = 0

thanks in advance ^^