im not sure i can fully remember the rules for complex numbers but i have to solve an equation that has 3 solutions to equal zero. so far i have (x=2), (x=i) and i think there was a + rule for a solution with complex numbers that there would always be a conjugate solution of it. so i figured that the last solution would be (x=-i) but when i try and solve it i keep getting different answers and they are all non zero.(adsbygoogle = window.adsbygoogle || []).push({});

i think i may be doing something wrong with the powers of the(-i)or it might be that i thought wrong and (x=-i) is not a solution.

could someone please confirm ths for me?

here is the equation:

x^3 - (2-i)*x^2 + (2-2*i)*x - 4 = 0

im trying to solve for:

(-i)^3 - (2-i)*(-i)^2 + (2-2*i)*(-i)- 4 = 0

thanks in advance ^^

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# Help solving a complex equation

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