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Help! Solving air drag projectile problem

  1. Apr 15, 2003 #1
    Since my other thread is lacking attention, perhaps it is more suitable here:

    I inserted some fixed constants and multiplied out

    (48/.5)(1-^e-.5t)(sin 45) + (9.8/.25)(1-(.5t) - e^-.5t) = 0

    (96 - 96e^-.5t)(sin 45) + 39.2(1-(.5t)-e^-.5t) = 0

    67.88 - 67.88^e-.5t + 39.2 - 19.6t - 19.6e^-.5 = 0

    107.2 - 87.48e^-.5t - 19.6t = 0

    107.2 - 19.6t = 87.48^e-.5t

    log(107.2 - 19.6t) = log(87.48^e-.5t)

    log107.2 - log19.6t = -.5tLog(87.48)

    2.030194 - log19.6t = -.5t(1.94198)

    1.045463 - log19.6t = -.5t

    -(1.045463 - log19.6t = -.5t)

    -1.045463 + log19.6t = .5t

    log19.6t = .5t + 1.045463

    10^(.5t + 1.045463) = 19.6t

    This is where Im stuck.
     
  2. jcsd
  3. Apr 15, 2003 #2

    Tom Mattson

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    Matt,

    Could you post the original problem, or a link to your other thread? I don't see what you're trying to do with this.
     
  4. Apr 15, 2003 #3
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