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just started ordinary differential equation class, and i have to find the general soln of the eqn: y'=y(3-y)... just started so i only know of the method of seperation of varibles.

Thought of multiplying the y through so it becomes:

y'=3y-y^2 then do..

dy/dx=3y-y^2 then... im stuck... I tried doing seperation of varibles by

Dividing 3y-y^2 to the other side so you get:

dy/3y-y^2=0? But that doesn't seem right.

Thought of multiplying the y through so it becomes:

y'=3y-y^2 then do..

dy/dx=3y-y^2 then... im stuck... I tried doing seperation of varibles by

Dividing 3y-y^2 to the other side so you get:

dy/3y-y^2=0? But that doesn't seem right.

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