HELP!!!Statics problem 1. The problem statement, all variables and given/known data A thin rod AB of length L=0.5m and mass m=1.0kg makes an angle of theta=60 degree with the horizontal. It is held in position by a horizontal light string attached at A as shown. A mass M is suspended from A by a second string. If the coefficient of friction between the rod and the ground at the point of contact B is mu(s)=0.50, what is the largest mass M that can be suspended such that the rod does not slip. Diagram: http://tinypic.com/view.php?pic=121slk5&s=4 3. The attempt at a solution we need to use the equilibrium conditions to solve the problem. therefore, Sigma(Fx)=0,Sigma(Fy)=0 and Sigma(torque)=0 Sigma(Fy)=FN-mg=0 therefore, normal force=mg=1*9.8=9.8N Sigma(Fx)=frictional force-exerted force=0 this is what I know for solving the problem so far...I know that I have to somehow relate the rod with the hanging mass. Ignoring the ways I attempted above, I think that i can get the mass by M=1.0kg*cos(30o) but I think it is not the correct answer. Can anyone help me with it? thank you very much.