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Help~ Stoke's Theorem

  1. Aug 27, 2007 #1
    Given the field [tex]H=\frac{1}{2}cos\frac{\phi}{2}\hat{\rho}-sin\frac{\phi}{2}\hat{\phi}[/tex],evaluate both sides of Stokes’ theorem for the path formed by the intersection of the cylinder [tex]\rho = 3[/tex] and the plane z = 2, and for the surface defined by [tex]\rho = 3[/tex], 0<z<2 , and z = 0, 0<[tex]\rho[/tex]<3.

    I have problem at [tex]\frac{1}{2}cos\frac{\phi}{2}\hat{\rho}[/tex] part.

    when i do line integral , the dot product of rho and phi will gives me zero

    but when i do surface integral, after doing the curl, i will get z vector, dot with the surface with z vector also, i will obtain a value but not zero.

    i cannot get LHS and RHS equal

    Anyone can help me solve this, thanks!
    Last edited: Aug 27, 2007
  2. jcsd
  3. Aug 27, 2007 #2


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    What have you done? The forum rules are that you need to show your work before you get some help.
  4. Aug 28, 2007 #3


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    I don't see how you got that. Can you post the line integral you evaluated?
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