Help~ Stoke's Theorem

  • Thread starter ngjingtao
  • Start date
  • #1
1
0
Given the field [tex]H=\frac{1}{2}cos\frac{\phi}{2}\hat{\rho}-sin\frac{\phi}{2}\hat{\phi}[/tex],evaluate both sides of Stokes’ theorem for the path formed by the intersection of the cylinder [tex]\rho = 3[/tex] and the plane z = 2, and for the surface defined by [tex]\rho = 3[/tex], 0<z<2 , and z = 0, 0<[tex]\rho[/tex]<3.

I have problem at [tex]\frac{1}{2}cos\frac{\phi}{2}\hat{\rho}[/tex] part.

when i do line integral , the dot product of rho and phi will gives me zero

but when i do surface integral, after doing the curl, i will get z vector, dot with the surface with z vector also, i will obtain a value but not zero.

i cannot get LHS and RHS equal

Anyone can help me solve this, thanks!
 
Last edited:

Answers and Replies

  • #2
siddharth
Homework Helper
Gold Member
1,130
0
What have you done? The forum rules are that you need to show your work before you get some help.
 
  • #3
siddharth
Homework Helper
Gold Member
1,130
0
when i do line integral , the dot product of rho and phi will gives me zero

I don't see how you got that. Can you post the line integral you evaluated?
 

Related Threads on Help~ Stoke's Theorem

  • Last Post
Replies
4
Views
721
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
4
Views
734
  • Last Post
Replies
2
Views
859
  • Last Post
Replies
8
Views
2K
  • Last Post
Replies
6
Views
2K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
1
Views
1K
Top