The letters A-M = 202, therefore N-Z = ?
This is the whole problem. It's driving me nuts. Help? =(
It could be 202 as from A-M, there are 13 letters and from N-Z, there are 13 letters or the number figure would have to equal the same. (Hope I haven't confused too much).
haha yeah, but that's too easy. If the puzzle isn't garbage the answer should be more satisfying...
if there's more than one answer, then any of these suffices, but then it becomes a "bad" riddle...
There isn't enough information to draw any conclusion about the answer.
Interesting, if very vague puzzle. I can come up with a couple answers that *work*, but they don't seem particularly correct. Something like vowels are worth so many points and consonants are worth so many. Or counting the numbers of straight versus curved lines and scoring them differently. But those don't seem particularly "right".
I suspect it's something a bit more strange, like the letters' translation into Morse code or ASCII values or something like that. It's interesting, to say the least.
Playing around, I noticed that the letters J, K, and Z never appear in the alphabetic spelling of numbers-- every other letter is represented (although "C" first appears in the number "decillion", which is WAY up there!) I found it odd, since "zillion" and "jillion" are often used to represent large made-up numbers, and those two letters (2 out of the 3) aren't even ever used in any numeric spellings, so it's quite fitting! Apparently, we need to officially define "jillion", "killion", and "zillion" so they'll show up!
Separate names with a comma.