- #1
BunDa4Th
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Help! Stuck on problem for 2 days.
A 75.0 kg stunt man jumps from a balcony and falls 26.0 m before colliding with a pile of mattresses. If the mattresses are compressed 0.950 m before he is brought to rest, what is the average force exerted by the mattresses on the stuntman? N
I am really confuse on how to do this problem. I tried finding V = sqrt(2gh)
so i can find the KE but seem to still get it wrong these are some of the steps i did
sqrt(2(9.8)(26)) = 22.57 then i find sqrto(2(9.8)(.950)) = 4.32
from there i use KE = 1/2mv^2
1/2(75)(22.57)^2 - 1/2(75)(4.32)^2
19102.7 - 699.84 = 18402.86 N which is completely wrong
I think i used the wrong mass for the second KE but not sure at all.
or would i have to set up the equation like this
1/2m_1v_1^2 = 1/2m_2v_2^2 and find for m_2 then solve it KE1 - KE2
any help would be great.
A 75.0 kg stunt man jumps from a balcony and falls 26.0 m before colliding with a pile of mattresses. If the mattresses are compressed 0.950 m before he is brought to rest, what is the average force exerted by the mattresses on the stuntman? N
I am really confuse on how to do this problem. I tried finding V = sqrt(2gh)
so i can find the KE but seem to still get it wrong these are some of the steps i did
sqrt(2(9.8)(26)) = 22.57 then i find sqrto(2(9.8)(.950)) = 4.32
from there i use KE = 1/2mv^2
1/2(75)(22.57)^2 - 1/2(75)(4.32)^2
19102.7 - 699.84 = 18402.86 N which is completely wrong
I think i used the wrong mass for the second KE but not sure at all.
or would i have to set up the equation like this
1/2m_1v_1^2 = 1/2m_2v_2^2 and find for m_2 then solve it KE1 - KE2
any help would be great.