A block of mass M resting on a 19.1° slope is shown. The block has coefficients of friction μs=0.788 and μk=0.482 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 1.86 kg. What is the minimum mass M1 that will stick and not slip? In terms of mass 1, following eqn can be written: m1g sin 19.1 - T - Ff = 0 which can be rewritten as: m1g sin 19.1 - T - m1g cos 19.1 (friction coefficient) = 0 right? since the object is at rest. then i found T by equating it to m2g (T = m2g...see the diagram as to why i have donet this) Hence m1g sin 19.1 - m2g - m1g cos 19.1 (0.788) = 0 and then solved for m1....but im not getting the right answer I dont understand why my approach is wrong...where did i go wrong here?