This is the context:

**A ladder of length**

A man weigthing 740N climbs 1 m along the ladder.

N

(counterclock wise direction is considered positive)

The equation of the torque (equilibrium) about the bottom of the ladder is:

N=0.

*l*=5m and weigth w_{ladder}=160N rest against a wall. its lower end is at 3m from the wall.A man weigthing 740N climbs 1 m along the ladder.

N

_{wall}is the reaction ladder-wall.(counterclock wise direction is considered positive)

The equation of the torque (equilibrium) about the bottom of the ladder is:

N

_{wall}*__4__-160*__1.5__-740*1*__(3/5).__I dont know how they get the equation especially the underlined coefficients.

My problem is that I dont know which distance to consider when computing for the torque in this case: the distance in respect to x axis, y axis or along the ladder.

I hope I was clear enough

Thank you

B