- #1
nofear001
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Ive been working on this and its a little tough: Whats the answer?
A roof tile falls from rest from the top of a building. An observer inside the building notices that it takes 0.20s for the tile to pass her window whose size is 1.6m. How far above the top of this window is the roof?
(Hint: 2 calculations- Use uniform acceleration equations)
How am i suppose to do this?
a=9.81m/s^2 (im in Canada we use 9.81 not 9.8)
t= 0.20s
d= ?
Vi= 0m/s
Vf=?
Thxs
A roof tile falls from rest from the top of a building. An observer inside the building notices that it takes 0.20s for the tile to pass her window whose size is 1.6m. How far above the top of this window is the roof?
(Hint: 2 calculations- Use uniform acceleration equations)
How am i suppose to do this?
a=9.81m/s^2 (im in Canada we use 9.81 not 9.8)
t= 0.20s
d= ?
Vi= 0m/s
Vf=?
Thxs