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Help: trigonometric equation

  1. Jan 19, 2006 #1
    [tex]x_1(cos\alpha-1) + x_2sin\alpha = 0 [/tex]
    [tex]x_1sin\alpha + x_2(-cos\alpha-1) = 0 [/tex]
    How to solve this equation? Can anyone help me?
  2. jcsd
  3. Jan 20, 2006 #2


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    It's a system of equations: 2 equations in 2 unknowns. That means you can solve it. Just solve for one unknown in terms of the other using the first equation, and then subsitute that into the second.
  4. Jan 20, 2006 #3
    Let me try...

    Solve equation 1:
    [tex]x_2 = \frac{-x_1(cos\alpha - 1)}{sin\alpha}[/tex]

    Substitute it to the second:
    [tex]x_1sin\alpha + \frac{-x_1(cos\alpha - 1)}{sin\alpha}(-cos\alpha-1) = 0[/tex]

    [tex]x_1sin\alpha + \frac{x_1(cos^2\alpha - 1)}{sin\alpha} = 0[/tex]

    [tex]2x_1sin\alpha = 0[/tex]

    What is the solutions for [tex]2x_1sin\alpha = 0[/tex]?
    Obviously one is [tex]x_1=0[/tex], but if [tex]sin\alpha = 0[/tex], then...
    Last edited: Jan 20, 2006
  5. Jan 20, 2006 #4


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    Well done. The point is, of course, that [tex]\alpha[/tex] is a number (not one of the variables) so these can be solved like any pair of equations for x1 and x2.
    Notice, by the way, that if [tex]sin\alpha= 0[/tex], your first step, dividing by that, would be invalid. You have to look at this case separately.
    If [tex]sin\alpha= 0[/tex], then [tex]cos\alpha[/tex] is either 1 or -1.

    What do your equations look like if [tex]sin\alpha= 0[/tex] and [tex]cos\alpha= 1[/tex]?

    What do your equations look like if [tex]sin\alpha= 0[/tex] and [tex]cos\alpha= -1[/tex]?
    Last edited: Jan 20, 2006
  6. Jan 20, 2006 #5
    HallsofIvy, thanks.
    [tex]2x_1=0 and 0=0 => x_1=0, x_2 [/tex] could be any number
    [tex] 0=0 and -2x_2=0 => x_2=0, x_1 [/tex] could be any number

    I just try another solution.
    Rewrite the equations:
    [tex](x_1cos\alpha + x_2sin\alpha) - x_1 = 0 [/tex]
    [tex](x_1sin\alpha - x_2cos\alpha) - x_2 = 0 [/tex]

    Suppose [tex]x_1 = cos\frac{\alpha}{2}, x_2 = sin\frac{\alpha}{2}[/tex], then

    [tex]cos\frac{\alpha}{2}cos\alpha + sin\frac{\alpha}{2}sin\alpha - cos\frac{\alpha}{2} = 0 [/tex]

    [tex]cos\frac{\alpha}{2}sin\alpha - sin\frac{\alpha}{2}cos\alpha - sin\frac{\alpha}{2} = 0 [/tex]

    It works!

    I am wondering whether there is some general method to solve [tex]x_1, x_2[/tex] depending on [tex]\alpha[/tex] or not.
    Last edited: Jan 20, 2006
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