- #1

- 30

- 1

So my values are v_o=250m/s, r=120m, and angle=0 since they're on the same level, right? And I need to know v to subtract from 120m.

I would just like to know what equation to use, not the answer to the problem. Thank you.

- Thread starter kashmirekat
- Start date

- #1

- 30

- 1

So my values are v_o=250m/s, r=120m, and angle=0 since they're on the same level, right? And I need to know v to subtract from 120m.

I would just like to know what equation to use, not the answer to the problem. Thank you.

- #2

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 956

Integrating (or, since this is a constant, just mutiplying)

v= -9.8t+ initial vertical velocity= -9.8t+ 0 so v= dy/dt= -9.8t.

Integrating that, y= -4.9t

Neglecting air resistance (which we have to since there is no information on air resistance) there is no horizontal acceleration:

a= dv/dt= 0 so v= initial horizontal velocity= 250 m/s. and then

x= 250t. To go 120 m, requires that 250t= 120. Solve that equation for t and use that t in y= -4.9t

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 4K

- Last Post

- Replies
- 4

- Views
- 1K

- Replies
- 3

- Views
- 592

- Last Post

- Replies
- 5

- Views
- 2K

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 1K

- Last Post

- Replies
- 5

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 1K