- #1
mprm86
- 52
- 0
Calculate [itex] e^A [/itex] if [itex] A = \left(\begin{array}{cc}0 & -2\\1 & 3\end{array}\right) [/itex]
Maybe using that [tex] e^x = \sum_{n=0}^\infty \frac{x^n}{n!} [/tex], then
[tex] e^A = \sum_{n=0}^\infty \frac{\left(\begin{array}{cc}0 & -2\\1 & 3\end{array}\right)^n}{n!} [/tex]
but i don't know if this is the right way for doing this. Please help me. Thanks.
Maybe using that [tex] e^x = \sum_{n=0}^\infty \frac{x^n}{n!} [/tex], then
[tex] e^A = \sum_{n=0}^\infty \frac{\left(\begin{array}{cc}0 & -2\\1 & 3\end{array}\right)^n}{n!} [/tex]
but i don't know if this is the right way for doing this. Please help me. Thanks.