Calculate [itex] e^A [/itex] if [itex] A = \left(\begin{array}{cc}0 & -2\\1 & 3\end{array}\right) [/itex](adsbygoogle = window.adsbygoogle || []).push({});

Maybe using that [tex] e^x = \sum_{n=0}^\infty \frac{x^n}{n!} [/tex], then

[tex] e^A = \sum_{n=0}^\infty \frac{\left(\begin{array}{cc}0 & -2\\1 & 3\end{array}\right)^n}{n!} [/tex]

but i dont know if this is the right way for doing this. Please help me. Thanks.

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# Help whit a problem. (I have no idea)

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