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cweed
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I am working to determine what the temperature loss (minimal at best) would be by mixing a stream of water flowing at 2,400 gph at 85 degree (f) into another stream of water flowing at 37,000 gph. Any help would be great
cweed said:Yes the final temperature of the two stream the one at flowing 2,400 gph is 85 (f) and the one flowing at 37,000 gph is 105 (F).
The formula for calculating temperature loss for mixing water streams is: (T1 x V1 + T2 x V2) / (V1 + V2) = Tm, where T1 and T2 are the temperatures of the two water streams, V1 and V2 are the volumes of the two water streams, and Tm is the resulting mixed temperature.
The temperatures should be in degrees Fahrenheit or Celsius, and the volumes should be in gallons or liters.
Yes, there are several factors that can affect the accuracy of the calculation, such as the flow rates of the water streams, the efficiency of the mixing process, and any heat loss from the mixing vessel.
There is no specific method, but it is important to use consistent units and measure the temperatures and volumes accurately to ensure an accurate calculation. It is also recommended to take multiple measurements and average them for a more precise result.
Yes, this calculation can be used for any type of fluid as long as the units for temperature and volume are consistent. However, different fluids may have different properties that can affect the accuracy of the calculation, so it is important to consider these factors when using this formula for non-water fluids.