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I have to calculate the integral of the function sqrt(x^2+y^2) over the circle (x-1)^2+y^2<=1

I use polar coordinates: rho goes from 0 to 2cos(theta) and theta goes from 0 to 2pi.

My result is that the integral is 0... is it right?

- Thread starter eoghan
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- #1

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I have to calculate the integral of the function sqrt(x^2+y^2) over the circle (x-1)^2+y^2<=1

I use polar coordinates: rho goes from 0 to 2cos(theta) and theta goes from 0 to 2pi.

My result is that the integral is 0... is it right?

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tiny-tim

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Hi eoghan!

I have to calculate the integral of the function sqrt(x^2+y^2) over the circle (x-1)^2+y^2<=1

I use polar coordinates: rho goes from 0 to 2cos(theta) and theta goes from 0 to 2pi.

My result is that the integral is 0... is it right?

erm … doesn't theta go from -π/2 to π/2?

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