- #1
Morphayne
- 13
- 0
I need help differentiating this equation:
y=(x-1)^2(6^x)
What I have (I went wrong somewhere):
dy/dx = (x-1)[(x-1)(6^x)]
=(x-1)[6^x(1+ x ln6 - ln6)
=(x-1)6^x(1+ x ln6 - ln6)
So;
My final answer: (x-1)6^x(1+ x ln6 - ln6)
Answer in the textbook: (x-1)6^x(2+ x ln6 - ln6)
Please help. I need to understand this for a test tomorrow.
y=(x-1)^2(6^x)
What I have (I went wrong somewhere):
dy/dx = (x-1)[(x-1)(6^x)]
=(x-1)[6^x(1+ x ln6 - ln6)
=(x-1)6^x(1+ x ln6 - ln6)
So;
My final answer: (x-1)6^x(1+ x ln6 - ln6)
Answer in the textbook: (x-1)6^x(2+ x ln6 - ln6)
Please help. I need to understand this for a test tomorrow.