1. The problem statement, all variables and given/known data Double integral of y*e^(x^4-1) with bounds 0=<y=<1 y^(2/3)=<x=<1 2. Relevant equations 3. The attempt at a solution Well, the first key thing to recognize is that we need the correct order for the bounds to compute this double integral. So I switch it from x=y^(2/3) and x=1 TO y=x^(3/2) and y=1 and x=0 to x=1 becomes the x boundaries. So now I integrate with respects to the y boundary first as that is the only way to solve this problem. I get y^2/2*e^(x^4-1) from y=1 to y=x^(3/2) This then becomes the integral from x=0 to x=1 of 1/2(e^(x^4-1)-x^3*e^(x^4-1))dx And I am clueless on how to solve this. I've been trying to do u-substitution for a while now knowing that letting u = x^4-1 and du=x^3 I can work with something. Did I do something wrong in my previous steps?