- #1
FatoonsBaby71
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Homework Statement
The electric flux density in space is given as D = 2xy(ax)+x^2(ay) C/m^2. A box is given as: 0<=x<=1; 0<=y<=2;0<=z<=3 (m). It is found that the total electric flux out of the box is (Wo). The charges creating the electric flux density D are now removed and replaced by a sphere of radius a =0.2m centered at (0.2,0.2,0.2) m and charged with a uniform volume charge density d. It is found that the total electric flux out of the box again is (Wo). Find the volume charge density d.
Homework Equations
Double Intergral D * ds = Q (Gauss Law)
dflux = D* dS
Charge elements: Volume dQ = pv * dv
The Attempt at a Solution
Well i first found the total charge in side the box using gauss' law. Which resulted in 18 C. (Hope this is right!) Since we know that the flux is equal to the charge, I figured all i needed to do is use the equation dQ = pv * dv and solve for pv which is the volume charge density d. However how would I be able to do this, I can't divide dQ/dv = pv can I? Is this the logical way to go behind the problem??
Thanks for your help