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_{x}? If I do, would it just be A

_{x}- 400cos30 = 0?

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- Thread starter Ryuk1990
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- #1

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- #2

PhanthomJay

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Yes, but I couldn't find your calculation for determining x =20 feetI am to find the reactions at A. Am I doing this right?

Yes!Do I also need to find A_{x}?

and Yes again!If I do, would it just be A_{x}- 400cos30 = 0?

- #3

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Yes, but I couldn't find your calculation for determining x =20 feet

My bad. I used this following equation to find x.

300(20) = 100x + (400sin30)x

Is that the correct way of finding x?

- #4

PhanthomJay

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Yes, indeed.My bad. I used this following equation to find x.

300(20) = 100x + (400sin30)x

Is that the correct way of finding x?

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