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Help with gases PLEASE

  1. May 5, 2004 #1
    Can someone please calculate the volume occupied at STP by 2.99times10 to the 23rd power molecules of Chlorine. Thank you Very much.
     
  2. jcsd
  3. May 5, 2004 #2

    ShawnD

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    All gases have a specific size at STP. I think it's 22.4L IIRC. Just multiply 22.4 * (2.99 * 10^23) / (avogadro's number)
     
  4. Jun 9, 2004 #3
    avogadro's number = 6.02*10^23

    incase you didn't know
     
  5. Jun 10, 2004 #4

    Gokul43201

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    1. Use the Ideal Gas Law, PV =nRT, with n= [tex]\frac {2.99*10^{23}} {6.02*10^{23}} [/tex], to find V. You know, P, T, R, n.

    OR

    2. At STP, one mole of an ideal gas occupies 22.4 liters. One mole has 6.02*10^23 molecules. Use ratios to find the volume of 2.99*10^23 molecules.
     
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