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Help with Gauss' law

  • Thread starter catz
  • Start date
  • #1
1
0

Homework Statement


Trying to find E field inside a sphere radius a with volume charge density rho = k/r


Homework Equations



Gauss' law

The Attempt at a Solution



I set up a spherical shell radius R (R<a)
I found the charge inside by integrating rho from 0 to R (Q = 2*pi*a*R^2)

put these infos into gauss law, got E = k/(2(epsilon))

It just seems wierd that the E field inside is constant even though the volume density is not. I guess it might be because the surface area of the gauss shell increases with R but the density drops off as 1/R.

Also, integrating from the origin seems like it might be a mistake (rho -> inf as r-> 0)
 

Answers and Replies

  • #2
23
1


Rho is the volume charge density, correct? Is there something you're missing when you go to find the charge enclosed?
 
  • #3
2,685
20


Just a point of frustration on my part, please name your thread appropriately next time - I believe the rules do specify this.
 

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