Help with integral

1. Sep 12, 2004

krusty the clown

$$\int \frac {x}{\sqrt{3-x^4}}\mbox{dx}$$

Basically I haven't had any luck with anything I have tried. It almost looks like a trig substitution, but I don't know how to deal with the x^4 under the radical. Also, I would rather have a hint as to where to start rather than have the whole problem done for me.

-Thanks, Erik

2. Sep 12, 2004

Pyrrhus

Deal it as $$(x^2)^2$$

3. Sep 12, 2004

Tide

I think that's going to turn into an incomplete beta function.

4. Sep 12, 2004

krusty the clown

I'm not sure what this means, but this problem is from calc II, and the text specifically says there are answers to all of the questions from the section this was taken from.

Thanks. I am prety sure I can do this with trig substituion now, but if I can't I will let you know.

-Thanks, Erik

5. Sep 12, 2004

Tide

Right! I didn't look at it long enough. It's going to be an arcsin with an x^2 in the argument.

6. Sep 13, 2004

Pyrrhus

Read Tide's post he gave it away
No need for trigonometric substitution.

Hint!
$$u = x^2$$
$$\frac{du}{2}= xdx$$