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Now, i need to calculate Momentum before and after the collision (arbitrary units) and Kinetic energy before and after the collision (arbitrary units).

The diplacements of the Ball bearings after this collision are:

Displacement (B1) 0.614m at an angle 49degrees. The displacement of (B2) is 0.782m at an angle of 37degrees.

The two ball bearing are of exactly the same mass, hence using the equations: Ek = 1/2mv^2 and Ep = mgh allow me to sort of work out a expression for velocity..

1/2mv^2 = mgh

1/2v^2 = gh

1/2(s/t)^2 = gh

t = s/[(2gh)^(1/2)]

v = s/t

v = s/[(s/((2gh^(1/2)))]

v = (2gh)^(1/2)

However, we were not supposed to work out the height of the ramp relative to the floor.

Please help me! thanks alot!!