# Help with Limits

1. Sep 28, 2004

### buffgilville

Compute the limit of:
1) f(x) = 2(square root of (x^2 - 1))/(x+1)

as x approaches -1 from the right.

2) f(x) = 3(x+2)/(absolute value of x + 2)

as x approaches -2 from the left.

I got does not exist for both because and x>-1 and x<-2, respectively. Am I right?

2. Sep 28, 2004

### Leong

$$\begin{multline*} \begin{split} &f(x)=\frac{3(x+2)}{|x+2|}\\ &Approches\ -2\ from\ the\ left:\\ &x+2<0;\ |x+2|=-(x+2)\\ &f(x)=\frac{3(x+2)}{-(x+2)}\\ &f(x) approaches -3. \end{split} \end{multline*}$$