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Homework Help: Help with Limits

  1. Sep 28, 2004 #1
    Compute the limit of:
    1) f(x) = 2(square root of (x^2 - 1))/(x+1)

    as x approaches -1 from the right.

    2) f(x) = 3(x+2)/(absolute value of x + 2)

    as x approaches -2 from the left.

    I got does not exist for both because and x>-1 and x<-2, respectively. Am I right?
     
  2. jcsd
  3. Sep 28, 2004 #2
    [tex]
    \begin{multline*}
    \begin{split}
    &f(x)=\frac{3(x+2)}{|x+2|}\\
    &Approches\ -2\ from\ the\ left:\\
    &x+2<0;\ |x+2|=-(x+2)\\
    &f(x)=\frac{3(x+2)}{-(x+2)}\\
    &f(x) approaches -3.
    \end{split}
    \end{multline*}
    [/tex]
     
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