1. How do you solve log base a ((x-1)/(x+6)) = log base a ((x-2)/(x+3)) i think you can cancel the logs and it will be ((x-1)(x+3))/((x+6)(x-2)). i don't know where to go from there.the answer is 9/2. 2. 16^x + 4^(x+1) - 3 = 0 i simplified this to: 4^(2x) + 4^(x+1) - 3 = 0 then i substituted u for 4^x and got: u^2 + u - 3 = 0 but this cant be factored, the answers -0.315. how do i solve this?