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Help with mathematica

  1. Jun 3, 2010 #1
    Hello,

    1) I am trying trying to simulate a laser scattering experiment in Mathematica. So the first trouble I have is how to define a set of 3D points. I did this program in C++ like this:
    for (int i=0; i<3; i++)
    {
    pyr[0].point[0]=0;
    }
    for (int a=1; a<3; a++)
    {
    for (int b=0; b<3; b++)
    {
    if (b == 1) // adding sqrt(2) to the Y cordinate
    {
    pyr[a].point[0]=pyr[a-1].point[0]+ sqrt(2.0);
    }
    else
    {
    pyr[a].point[0]=pyr[a-1].point[0];
    }
    }
    }
    for (int c=0; c<3;c++)
    {
    if (c==0)
    {
    pyr[3].point[0][c]=pyr[0].point[0][c]+ sqrt(2.0);
    }
    else
    {
    pyr[3].point[0][c]=pyr[0].point[0][c];
    }

    }
    for(int d=4;d<6; d++)
    {
    for (int e=0;e<3;e++)
    {
    if (e == 1) // adding sqrt(2) to the Y cordinate
    {
    pyr[d].point[0][e]=pyr[d-1].point[0][e]+ sqrt(2.0);
    }
    else
    {
    pyr[d].point[0][e]=pyr[d-1].point[0][e];
    }
    }
    }
    for (int f=0; f<3;f++)
    {
    if (f==0)
    {
    pyr[6].point[0][f]=pyr[3].point[0][f]+ sqrt(2.0);
    }
    else
    {
    pyr[6].point[0][f]=pyr[3].point[0][f];
    }
    }
    for(int g=7;g<9; g++)
    {
    for (int h=0;h<3;h++)
    {
    if (h == 1) // adding sqrt(2) to the Y cordinate
    {
    pyr[g].point[0][h]=pyr[g-1].point[0][h]+ sqrt(2.0);
    }
    else
    {
    pyr[g].point[0][h]=pyr[g-1].point[0][h];
    }
    }
    }


    The question is, how do I define these points in Mathematica? Is there a way I can have multidimensional arrays and define the points like above and then use then for further calculations?

    Thanks in advance
    dg
     
  2. jcsd
  3. Jun 3, 2010 #2
    Define an empty matrix then use AppendTo (or Reap and Sow) to add elements in a loop or whatever.
     
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