ok this is the question: f(x) = 6x2 + 12x + c where C is a constant. a) Given f(x) =0 has equal roots, find the value of C. so this what i did for this part: b2- 4ac = 0 (formula for discriminant) 122-4(6xC) =0 144-24c=0 6-C=0 c=6 (is that right?) Now for the next part: b) Hence, solve f(x) = 0 6x2+12x+6=0 (x=1)(6x+6)=0 x=-1 x= -6/6 = -1 I wasn't really sure what i was doing but i tried to work it out and this is what i did but i'm not sure if it's right. (i don't think it is!) Can somebody help please!