I have this system :(adsbygoogle = window.adsbygoogle || []).push({});

[tex](A_1 \quad A_2 \quad A_3 \;...)\left( {\matrix{

{b_1 } \cr

{b_2 } \cr

{b_3 } \cr

{...} \cr

} } \right) = C[/tex]

where the A's are matrices that forms a vector, b is a vector and C a matrix. If I know C and the A's. How can I find the b's?

[tex]\left( {\matrix{

{b_1 } \cr

{b_2 } \cr

{b_3 } \cr

{...} \cr

} } \right) = (A_1^{ - 1} \quad A_2^{ - 1} \quad A_3^{ - 1} \;...)C

[/tex]

Surely not, this give another matrix. The A's are square but not necessarely invertable...

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Help with matrices

**Physics Forums | Science Articles, Homework Help, Discussion**