1) A cardboard box of 32in^3 volume with a square base and open top is to be constructed. Find the minimum area of cardboard needed.
Since it has a square base, length and width must be the same, variable b for base.
So volume could be written as: hb^2=32 and surface area as b^2+4bh=min.
Once I get here, I''m not quite sure what to do.
Any help is greatly appreciated!
Since it has a square base, length and width must be the same, variable b for base.
So volume could be written as: hb^2=32 and surface area as b^2+4bh=min.
Once I get here, I''m not quite sure what to do.
Any help is greatly appreciated!