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**1. Homework Statement**

A decorative paperweight of mass 0.50 kg. sits on a desktop. The coefficient of friction is 0.60.

a) How much force in the horizontal direction is needed to make the paperweight just move?

b) What is the net force on the paperweight at the instant it begins to move (with negligible acceleration)?

**2. Homework Equations**

coefficient of friction = Force to push paperweight / Weight of paperweight

weight = (mass)(gravity)

**3. The Attempt at a Solution**

a) w = mg = .50 kg. (9.81 m/s^2) = 4.905 N

coefficient of friction = Force to push paperweight / Weight of paperweight

Derivation: Weight of paperweight x coefficient of friction = Force to push paperweight

4.905 N x 0.60 = 2.943 N

b) I'm not really sure with this, but I think the net force is still 2.943 N because I read somewhere that "If there is just one force on an object, then that force is the net force."

Can someone help me with this? And please check if my answers are correct?