# Help with permutation cycles

1. Jan 23, 2005

### frb

can anyone explain me the technique to decompose a random n-cycle into a bucnh of 2 cycles. Thanks in advance.

2. Jan 23, 2005

### robert Ihnot

Look at: (ab)(ac). Approaching this from the left, we have (1) a goes to b. (2) b goes to a in cycle one, and then a goes to c in cycle two. (3) As for c it is sent into a, cycle two.

Thus (abc)=(ab)(ac). And so forth, (abcd) = (ab)(ac)(ad), etc.

Last edited: Jan 23, 2005