(adsbygoogle = window.adsbygoogle || []).push({}); There's a metal cylinder from which water is flowing out at a rate of 10^-6 m^3/s. A tuning fork of 300 Hz is placed on top of the cylinder. At what water levels will the first two resonance frequencies be heard?

It doesn't seem like a difficult problem, and it really isn't. I just can't seem to see it.

I dont think the flow rate has any signifiance in calculation; it's only useful to know that the water level is decreasing.

It's an open-closed system, so the natural frequencies are [tex]f_n = \frac{nv}{4L} [/tex] where n = 1, 3, 5, 7....

So in the first case, i think the first frequency heard would be 300 Hz. Hence, one can solve for [tex]L_1[/tex] to attain 0.286m. But how about for the next? Will it just be 3 times L_1 ? Or how do you solve for it otherwise?

Thanks

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Question 2: Is it logical to ask whether the beat frequency is e.g. +4 or -4? Afterall, [tex]f_{beat} = |f_2 - f_1| [/tex] so because of the absolute value,it is always +4.

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# Homework Help: Help with physics resonance

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