Help with power energy problem

In summary: So we can write:dE/dt = -power = -a0 + btThis is what you want to integrate. And you can use the fact that you know that at the start, t=0, the energy is 8.1 × 108 J. And at the end, t=4, the energy is zero. So you have two bits of information to help you work out a0 and b. But you have to be careful with the units. They give you hours, but that's not the SI unit of time. You need to convert to seconds.
  • #1
awais1985
8
0
I was working on the following problem:

Determine the power output as a function of time from an energy storage device for a four hour discharge period when it is known that for this type of system the power is a linear function of time, (Power) = a0 - bt, where a0 = 1.1(105) W, b is a constant and t is the time. The energy stored in the device at the star of this process is 8.1(108) J. Using your result calculate the power delivered at 2.4 hours into the discharge process.

Solution:

What i did was integrate the power equation to come up with an energy equation since

energy is the integral of power w.r.t time. i got the following expression

Energy = Energy (at t=0) – (bt2)/2

Now we are given that At t=0; Energy = 8.1 × 108 J

t=1; Energy = 8.1 × 108 – b/2
t=2; Energy = 8.1 × 108 – 2b
t=3; Energy = 8.1 × 108 – 9b/2
t=4; Energy = 8.1 × 108 – 8bAt t=2.4; Energy =8.1 × 108 – 5.76b/2I don't know how to calculate 'b' here. Am i doing it right or should i change my approach?<< Unnecessary link deleted by Moderator >>
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
awais1985 said:
energy is the integral of power w.r.t time. i got the following expression

Energy = Energy (at t=0) – (bt2)/2
Yes, energy is the integral of power w.r.t. time, but you have missed out one of the terms. What happened to the a0 term?

awais1985 said:
I don't know how to calculate 'b' here. Am i doing it right or should i change my approach?
yes, your approach is mostly right. (apart from the missed out term). They tell you how much energy there is to begin with, and imply how much energy there is at the end. So you can use this to calculate the unknown parameters.

Oh, and welcome to physicsforums :)
 
  • #3
Thanks man. Yes, i corrected that and i got

Energy = a0t –bt^2/2

So here is the thing..when i put t=0 ...energy comes out to zero whereas we are given that energy at the start is 8.1 × 108 J. i am not understanding this.
 
  • #4
Also, if i consider the ao term , how can i write 8.1 × 10^8 in its place?

at t=1; Energy = 8.1 × 108 – b/2
 
  • #5
awais1985 said:
Thanks man. Yes, i corrected that and i got

Energy = a0t –bt^2/2

So here is the thing..when i put t=0 ...energy comes out to zero whereas we are given that energy at the start is 8.1 × 108 J. i am not understanding this.
It's almost right. There will be another term, the constant of integration. And this will let you make sure that the initial energy is correct.
 
  • #6
Energy = a0t – bt2/2 + c

Will this mean that c is 8.1 × 10^8? I still don't know how will i calculate b?

This problem is frustrating!
 
  • #7
keep with it! you've done most of the work. And yes, c is 8.1 × 10^8. To calculate b is not difficult, but they did not ask the question very well. They say a 'four hour discharge period'. I'm pretty sure this is meant to imply there is zero energy left in the device when the 4 hours is done. You are explicitly told how much energy there is at t=0, so you can use these bits of information to get b.
 
  • #8
Can i equate Energies?

t=0; Energy = 8.1 × 108 J
t=1; Energy = a0 – b/2 + c

8.1 × 108 J = a0 – b/2 + c
1.1 × 105 = b/2
b= 5500
 
  • #9
that was b = 220000
 
  • #10
No wait, sorry, I think they are implying that when the power output gets to zero, the 'four hour discharge period' has finished. i.e. power=0 when t=4 hours. This makes more sense, otherwise the power would go negative if we assume zero energy at t=4 hours.

So, use power=0 at t=4 hours. p.s. be careful with the units. They give you hours, but that's not the SI unit of time.
 
  • #11
okay, so i am totally confused now. I thought power and energy the same thing basically with the exception that power gives the amount of energy per time. So, how can energy be negative if power reaches zero? I am sorry i am annoying you repeatedly.
 
  • #12
no, it's important questions. uh, so yeah, power is energy per time. And in this problem, the device initially has some energy stored in it. Then it does this 'four hour discharge period', where energy goes out of the device. And they have used the convention that positive power means energy leaving the device. So, during this 'four hour discharge period', the power is always positive (since energy is always leaving the device). And during this 'four hour discharge period', the power output is slowly decreasing until it reaches zero. In other words, to begin with, the energy is flowing out of the device quickly, then less quickly, then even less quickly, until eventually the energy stops flowing at 4 hours.
 
  • #13
This is what it seems the question is implying. They don't really say explicitly. You should think it through too, and think of what is most likely that they want you to assume. So, anyway, if we are talking about power output, then the rate of change in energy of the device is going to be the negative of this.
 

What is a power energy problem?

A power energy problem refers to any issue or challenge related to the production, distribution, or consumption of energy. This can include issues such as shortages of energy sources, inefficient use of energy, or environmental concerns related to energy production.

How do power energy problems affect our daily lives?

Power energy problems can have a significant impact on our daily lives. For example, if there is a shortage of energy, it can lead to power outages and disruptions in our daily routines. Additionally, the use of certain forms of energy can have negative effects on the environment, which can affect our health and well-being.

What are some potential solutions to power energy problems?

There are various solutions that can be implemented to address power energy problems. These can include investing in renewable energy sources, improving energy efficiency, and implementing policies to reduce energy consumption. Additionally, using a mix of different energy sources can also help to address power energy problems.

How can individuals help with power energy problems?

There are several ways that individuals can help with power energy problems. This can include reducing energy consumption in our daily lives by using energy-efficient appliances, turning off lights and electronics when not in use, and using alternative modes of transportation. It is also important for individuals to support policies and initiatives that promote sustainable energy production and consumption.

What role does government play in addressing power energy problems?

Governments play a crucial role in addressing power energy problems. They can implement policies and regulations to promote the use of renewable energy sources, encourage energy efficiency, and reduce energy consumption. Governments can also invest in research and development of new technologies to improve energy production and distribution. Additionally, they can provide incentives and subsidies to individuals and businesses to adopt sustainable energy practices.

Similar threads

  • Introductory Physics Homework Help
Replies
6
Views
224
  • Introductory Physics Homework Help
Replies
10
Views
942
  • Introductory Physics Homework Help
Replies
13
Views
3K
  • Introductory Physics Homework Help
Replies
24
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
23
Views
1K
  • Introductory Physics Homework Help
2
Replies
35
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
12
Views
840
Back
Top