Help with Quadratic Equations?

In summary: I think he died in a duel because he was just 20 years old. Young people often do very stupid things.
  • #1
Poweranimals
68
0
Any idea how to figure this problem out?

x + 1 = 9x^3 + 9x^2
 
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  • #2
Poweranimals said:
Any idea how to figure this problem out?

x + 1 = 9x^3 + 9x^2

First off, this belongs in a different section. General math, or homework help.

It's fairily easy to solve. What have you tried?
 
  • #3
In addition to NateTG's point that this is NOT a differential equation, it also is NOT a quadratic equation. It is a cubic equation that can be reduced to the standard form 9x3+ 9x2- x- 1= 0.

There exist a general formula for cubics but it is difficult to apply. Sometimes the simplest way to solve an equation is to cross your fingers and see what happens if you plug in simple numbers for x! (Hint: try negative numbers first.)
 
  • #4
Poweranimals said:
Any idea how to figure this problem out?

x + 1 = 9x^3 + 9x^2

Hi ,
You can solve this equation using the cardon methods which can be found in the any linear algebra book
 
  • #5
Poweranimals said:
Any idea how to figure this problem out?

x + 1 = 9x^3 + 9x^2

Hi ,
You can solve this equation using the cardon methods which can be found in the any linear algebra book

Dinesh
 
  • #6
Poweranimals said:
Any idea how to figure this problem out?

x + 1 = 9x^3 + 9x^2

This one is simple. Really simple actually...

x + 1 = 9x^3 + 9x^2
x + 1 = 9x^2(x + 1)
9x^2(x + 1) - (x + 1) = 0
(x + 1)(9x^2 - 1) = 0
x + 1 = 0 => x = -1
9x^2 - 1 = 0 => x = +- 1/3

So:
x_1 = -1
x_2 = 1/3
x_3 = -1/3

No need for cardano or anything
 
  • #7
Or simply try x= -1 as I originally suggested to find that
-1+1= 0= 9(-1)3+ 9(-1)2 so that x= -1 is a root. Once you know that, it is easy to see that 9x3+ 92-x-1=(x+1)(9x2-1)= (x+1)(3x-1)(3x+1).
 
  • #8
Does anyone know a link to the proof which shows that there exists no exact solution for equations of order 5 and above? Sorry I don't happen to know the exact terms for this.
 
  • #9
It is not going to be easy. Type Galois on google. Don't read his theory, it is too difficult. Read about his life, it is fascinating. We are very proud of Galois back in France :approve:

To Dinesh : they are also proud of Cardan back in Italy. :grumpy:
 
  • #10
There is a thread in this forum with galois stuff in it. titled cubic formula started by atcg, it's on the first page of the current topics somewhere.
 
  • #11
It's not, by the way, true that "there is no exact solution". What is true is that there exist polynomial equations with solutions that cannot be written as radicals (roots of roots of ... rational numbers).
As pointed out, Galois theory is very deep. Essentially, group theory originated as a way or simplifying the proof!

The idea:
1. A polynomial equation is "solvable by radicals" if and only if the Galois group of the polynomial is a "solvable group".
2. For any positive integer, n, there exist a polynomial of degree n whose Galois group is isomorphic to Sn, the group of permutations on n objects.
3. If n> 4, Sn is not a solvable group.
 
  • #12
Galois died so young. He would have brought to humanity such a wider math landscape. :cry:
 
  • #13
IIRC from a 6th grade report on him didn't he die in a duel? tsk tsk. Different times, I suppose.
 
  • #14
Yes, he fought a duel with a rival over some girl who wasn't worth half of him.

There was, by the way, a suggestion that the duel was set up by the duel was "set up" by government agencies. This was during the short time right after the defeat of Napolean when the Bourbons were back on the throne. There is, in fact, no evidence for that, although Galois did spend a year in prison just before this for "threatening the life of the King".
 
  • #15
It is very much more likely that he did not care about the girl. He constantly said that he would give his life if that could trigger revolution. Apparently, he decided himself to organise the duel, and die. But the same day, other events (a general murdered) triggered the "commune" revolution. So after all, he died for nothing.

The truth is : nobody knows for sure. That is what is fascinating. The thing is : Galois was so clever, why would he stupidely die in a duel ?
 

1. How do I solve a quadratic equation?

To solve a quadratic equation, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Alternatively, you can factor the equation or use the completing the square method.

2. What are the different forms of a quadratic equation?

The three main forms of a quadratic equation are: standard form (ax^2 + bx + c = 0), vertex form (a(x-h)^2 + k), and factored form (a(x-r1)(x-r2) = 0).

3. How do I identify the roots/solutions of a quadratic equation?

The roots/solutions of a quadratic equation are the values of x that make the equation equal to 0. You can find these values by factoring the equation, using the quadratic formula, or graphing the equation and finding the x-intercepts.

4. What is the discriminant in a quadratic equation and how is it used?

The discriminant is a value calculated from the coefficients of a quadratic equation, given by b^2 - 4ac. It is used to determine the nature of the roots of the equation. If the discriminant is positive, there are two distinct real roots. If it is zero, there is one real root. And if it is negative, there are no real roots.

5. Can I use the quadratic formula to solve any quadratic equation?

Yes, the quadratic formula can be used to solve any quadratic equation, regardless of its form or the values of its coefficients. However, there are other methods such as factoring and completing the square that may be more efficient for certain equations.

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