- #1
Poweranimals
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Any idea how to figure this problem out?
x + 1 = 9x^3 + 9x^2
x + 1 = 9x^3 + 9x^2
Poweranimals said:Any idea how to figure this problem out?
x + 1 = 9x^3 + 9x^2
Poweranimals said:Any idea how to figure this problem out?
x + 1 = 9x^3 + 9x^2
Poweranimals said:Any idea how to figure this problem out?
x + 1 = 9x^3 + 9x^2
Poweranimals said:Any idea how to figure this problem out?
x + 1 = 9x^3 + 9x^2
To solve a quadratic equation, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Alternatively, you can factor the equation or use the completing the square method.
The three main forms of a quadratic equation are: standard form (ax^2 + bx + c = 0), vertex form (a(x-h)^2 + k), and factored form (a(x-r1)(x-r2) = 0).
The roots/solutions of a quadratic equation are the values of x that make the equation equal to 0. You can find these values by factoring the equation, using the quadratic formula, or graphing the equation and finding the x-intercepts.
The discriminant is a value calculated from the coefficients of a quadratic equation, given by b^2 - 4ac. It is used to determine the nature of the roots of the equation. If the discriminant is positive, there are two distinct real roots. If it is zero, there is one real root. And if it is negative, there are no real roots.
Yes, the quadratic formula can be used to solve any quadratic equation, regardless of its form or the values of its coefficients. However, there are other methods such as factoring and completing the square that may be more efficient for certain equations.