1. Nov 10, 2008

lavenderblue

If a1=a2=a then show that any linear combination
(psi)=a1(psi)1 + a2(psi)2, where a1 and a2 re arbitrary complex numbers, is also an eigenstate with th same eigenvalue i.e. show that A(psi)=a(psi)

Could you please show your full workings I don't know where to start :(. Thanks!!

Here's what I thought might be right, but i'm not quite sure....

where A(psi)1=a(psi)1 and A(psi)2=a(psi)2
<A> = the integral (psi)*(A)(psi)

Last edited: Nov 10, 2008
2. Nov 10, 2008