# Help with series circuits

1. May 8, 2010

### alan1592

1. The problem statement, all variables and given/known data
First problem is a series circuit with 3 resistors. R1,R2,R3 is 3.0 ohms. This is all powered by a 3.0 V battery.

What is the current threw resistor 2?

2. Relevant equations
V=IR

3. The attempt at a solution

3.0=I(3.0)

Divide both sides by 3.0 and I got 1
.. the correct answer is 0.33 OHMs

2. May 8, 2010

### Lunat1c

First of all, the units of current are Amps. I also believe that you misread the question. The total resistance is not 3ohms, instead EACH resistor has a resistance of 3 ohms. So you need to find the equivalent series resistance first, and then apply ohm's law and get the correct answer of 0.33A.

3. May 8, 2010

### johnnyies

erm. . . check your solutions, current is not measured in Ohms.

First, find equivalent resistance, and remember that current thru a series of resistors is the same.

4. May 8, 2010

### alan1592

Ok I got the right answer. I got the total resistance and divide it by the volts and i got the current. Thanks guys! What if I have another question on this same sort of problem do i make another thread? Or should i just ask here?

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