Solve Math Problem: Finding i Given i_a and n Terms

  • Thread starter badman
  • Start date
In summary, the person is trying to solve a complex number problem where they need to find i given i_a and n. They are unsure of how to proceed and are seeking help. Another person suggests that solving the equation is just taking a root. They provide two possible solutions depending on whether (i+1)^n-1 is supposed to be (i+1)n-1 or (i+1)n-1.
  • #1
badman
57
0
i forgot how to do this type of problem and i i was wondering if you guys can help me out.


(1+i)^n-1=i_a I am trying find i given i_a. n is the number of terms which i also have. i know u have to add the negative one to the other side. but no clue as to go from there.
 
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  • #2
anyone help?
 
  • #3
Is this a complex number problem? What is i_a? Is it just a constant?
 
  • #4
You won't get much help if you don't state the problem more clearly. Can I take it that i and i_a are just numbers- If you are given i_a, solve for i?
Even then is (i+1)^n-1 supposed to be (i+1)n-1 or (i+1)n-1?

In either case solving the equation is just taking a root.
If [itex](i+1)^{n-1}= i_a[/itex] then [itex]i+1= ^{n+1}\sqrt{i_a}[/itex] so [itex]i= ^{n+1}\sqrt{i_a}-1[/itex].
If [itex](i+1)^n-1= i_a[/itex] then [itex](i+1)^n= i_a+1[/itex] so
[itex]i+1= ^n\sqrt{i_a+1}[/itex] and [itex]i= ^n\sqrt{i_a+1}-1[/itex].

([itex]^n\sqrt{}[/itex] is the nth root.)
 
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