- #1
badman
- 57
- 0
i forgot how to do this type of problem and i i was wondering if you guys can help me out.
(1+i)^n-1=i_a I am trying find i given i_a. n is the number of terms which i also have. i know u have to add the negative one to the other side. but no clue as to go from there.
(1+i)^n-1=i_a I am trying find i given i_a. n is the number of terms which i also have. i know u have to add the negative one to the other side. but no clue as to go from there.